PhysicsLAB Resource Lesson

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In order for an object to gain energy, work must be done on it by an external force. When work is done on an object by a force acting parallel to its displacement the formula is:
workdone = force x displacement
For positive work to be done, F and s must be parallel and pointed in the same direction. The unit used to measure work and energy is a joule. [J = kg m2/sec2 = Nm]
Work done by non-conservative forces
If we look at the forces on an object being pulled across a table's surface there would be three: F, the applied force, N, the normal or supporting force supplied by the table, and mg, its weight or the gravitational force of attraction to the earth.
The normal force and the object's weight are in static equilibrium (they are balanced forces), the applied force, F, is an unbalanced force and will result in the object being accelerated across the top of the table's surface in the same direction as the force. This acceleration will change the object's velocity and subsequently its kinetic energy. We say that this applied force is doing work on the object. The amount of work done by F is directly proportional to the distance through which the force is applied as it pulls the object across the table's surface.
net Workdone = (net F)s
By using Newton's second law, net F = ma, our equation becomes

net Workdone = (ma)s
net Workdone = m(as)
Remembering the kinematics equation vf2 = vo2 + 2as and solving for "as" let's our equation become

net Workdone = m[½(vf2 - vo2)]
net Workdone = ½(mvf2 - mvo2)
net Workdone = ½mvf2 - ½mvo2
net Wdone = ΔKE
The relationship we just derived is called the energy-work theorem..
This statement tells us that when an external force does work on an object it will change the object's kinetic energy; that is, it will cause the object to either gain or lose speed. When more than one force is acting on an object, all forces that are either parallel or antiparallel to the direction the object moves will do work. If the object's velocity remains constant, that just means that the work done by opposing forces (for example, a forward applied force, F, and an opposing force, friction) are equal.
Note that if F and s are perpendicular to each other no work is done on the object.  In our  example of the block being dragged across the table, neither the normal force nor the weight would do any work on the block since they act at right angles to the direction of the block's motion. Another example would be when a satellite is being held in circular orbit by the force of gravity. Note that since the satellite's speed and orbital radius remain constant, no energy is being changed; therefore, no work is being done on the satellite.
Work done by conservative forces
Work done by conservative forces, or path-independent forces, results in changes in the object's potential energy.
Let's use gravity an example of a CONSERVATIVE FORCE (or path-independent force). Remember that the changes in an object's potential energy only depend on comparing its starting position and its ending position, not on whether it does or does not pass through various points in-between. The block's final change in potential energy is the same whether it follows the path with the intermediate stops B, C and D or whether it is directly taken from A to E. The height of the post is the same.
When you observe an object falling, it loses potential energy (height) while it gains kinetic energy (speed). That is, in the absence of another external, non-conservative force, such as friction, pushing/pulling, or tensions in strings, the total amount of potential energy before the fall equals the total amount of kinetic energy after the fall and the energy-work theorem is restated as the Law of Conservation of Energy:
Workdone = ΔKE
Workdone conservative force= - ΔPE

- (PEf - PEo) = KEf - KEo
- PEf + PEo = KEf - KEo

KEo+ PEo = KEf + PEf
For projectiles in freefall this statement of conservation of energy can be used to compare the energies at two different locations (A and B) in its trajectory:
Refer to the following information for the next two questions.

Suppose a baseball player throws a baseball at a speed of 40. meters per second at an angle of 30. degrees to the ground. Use energy methods to determine each of the following.
 (a) the height of the apex

 (b) how fast the baseball is traveling while passing just above a 3-meter fence located at the extreme edge of the field.

Remember that energy (as well as work) is a scalar. The velocity in the KE formula represents the RESULTANT velocity or the actual instantaneous SPEED of the object. You do not take x and y components. This formula could also be used to determine the speed of a cart on a frictionless roller coaster, or a bead on a frictionless wire.
The formula used to calculate the power delivered or developed to complete a specified amount of work in a given time is
Power = work/time
Power is measured in watts. [watt = J/sec]
workslopepower.gif (3324 bytes)
A second form of power is easily derived.
Power = work/time
Power = (Fs) / t
Power = F (s/t)
Power = Fv
This expression can only be used when either the velocity is constant or when only an instantaneous value for power is being requested.

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