Practice Problems
Uniform Acceleration: SVA Graphs
Topics:
On this worksheet you will have the opportunity to practice three different sets of relationships between families of position-time, velocity-time, and acceleration-time graphs. Please note that the diagrams are not drawn to scale.
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The numerical values in this worksheet are randomly generated allowing students the opportunity to conveniently practice, and drill, common situations.
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omit
Question 1
Scenario #1
For these graphs,
t
1
= 4 seconds, t
2
= 12 seconds, and v
f
= -5 m/sec
.
If the uniform acceleration between 4 and 12 seconds was
a = 2 m/sec
2
, then what was the value of v
o
?
8 time
16 deltaV
-21 correct
2 acc
omit
Question 2
In
Question #1
, if the position of
point y equals 27 meters
, then what is the value of P?
-168 vot
-104 displacment
-21 original-velocity
131 correct
omit
Question 3
In
Question #1
, what was the object's average velocity between 4 and 12 seconds?
-13 correct
16.375 final/4
13 mathAverage
-168 at
8 midpoint
omit
Question 4
Scenario #2
For these graphs,
t
1
= 4 seconds, t
2
= 12 seconds
. In addition, the positions of y and P in meters are:
y = 27 m
and
P = 39 m
.
If the value of
v
f
= -7.5 m/sec
, then what is the value of v
o
?
1.05 x 10
1
m/sec
omit
Question 5
In
Questions #4
, what is the value for the object's acceleration, a?
-2.25 x 10
0
m/sec
2
omit
Question 6
For these graphs,
t
1
= 4 seconds, t
2
= 14 seconds, v
o
= 8 m/sec, and v
f
= 13.5 m/sec
2
.
What was this object's uniform acceleration, a?
0.550 m/sec
2
omit
Question 7
What was the object's displacement during the time interval graphed?
107.5 m
omit
Question 8
Scenario #3
For these graphs,
t
1
= 5 seconds, t
2
= 12 seconds, v
o
= 13.5 m/sec
, and
v
f
= 8 m/sec
.
If the position of
y equals -27 meters
, then what is the value of P?
-2.75wrong
-48.5 m
omit
Question 9
In which set does the object have a positive acceleration despite the fact that it is losing speed?
Question 8
Question 6
Question 1
Question 4
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