Directions: On this worksheet you will be investigating the relationships between momentum and energy.

Question 1
If F_{max} = 16 N and F_{min} = -10 N then calculate the impulse delivered to a 3-kg mass during the 5 seconds graphed above.

2 N sec1 N sec31 N sec41 N sec-9 N sec

Question 2
If the object's initial velocity in Question 1 was 7.6 m/sec, what will be its final velocity at the end of these 5 seconds?

-7.3 m/sec4.6 m/sec23.8 m/sec2.9 m/sec7.9 m/sec

Question 3
What was the magnitude of the average force acting on the 3-kg mass in Question 1 during the 5 seconds displayed on the graph?

3 N5 N0.2 N6.2 N-1.8 N

Question 4
A 7.6-gram bullet moving at 280 m/sec travels through a block of wood and emerges out the other side moving at 210 m/sec. If it takes 28.5 µsecs (1 µsec = 1 x 10^{-6} seconds) for the bullet to bore through the wood, what average force did the wood exert on the bullet?

-1.87 x 10^{4} N1.31 x 10^{6} N5.6 x 10^{4} N7.47 x 10^{4} N

Question 5
During target practice, a man shoots a 7.6-gram bullet with a horizontal velocity of 210 m/sec at a 1.5-kg wooden block balanced on the top of a 1-meter tall fence post. If the bullet embeds in the block, how fast will the block-bullet be knocked off the post?

208.94 m/sec1.06 m/sec140 m/sec0.054 m/sec

Question 6
After being knocked off, how far from the base of the fence post will the block in Question 5 hit the ground?

0.94 m0.48 m0.22 m0.67 m0.34 m

Question 7
A second 7.6-gram bullet is fired at another 1.5-kg block which is initially at rest on a table. The bullet embeds in the block resulting in the block sliding 172 centimeters before coming to a stop. The coefficient of friction between the block and the table's surface is µ = 0.367.How much work will the friction between the table and block do on the block while bringing it to a stop?

63.1 J25.4 J9.3 J3.2 J5.4 J

Question 8
How fast was the original bullet in Question 7 travelling before it struck the block?

Question 9
As shown in the diagrams provided below, a ball of mass 1 kg is originally moving along the x-axis with a velocity of 10 m/sec towards the origin. As it approaches the origin, it delivers a glancing blow to a stationary 2-kg mass. After the collision, the 1-kg ball continues traveling towards the left, into the second quadrant, at a reduced speed of 5 m/sec at an angle of 37º above the negative x-axis.

What is the final momentum of the 2-kg mass after the collision?

6.7 kg m/sec3 kg m/sec13.4 kg m/sec6 kg m/sec5 kg m/sec

Question 10
Within the system, what fraction of the 1-kg ball's original KE remains after the collision?